734B - Anton and Digits - CodeForces Solution


brute force greedy implementation math *800

Please click on ads to support us..

Python Code:

k2,k3,k5,k6=[int(_) for _ in input().split()]
suma=0
if min(k5,k6)!=0 and k2>0:
    suma=min(k2, min(k5,k6))*256
if k3>0 and k2-min(k2, min(k5,k6))>0:
    suma+=min(k3,k2-min(k2, min(k5,k6)))*32
print(suma)


Comments

Submit
0 Comments
More Questions

1703A - YES or YES
494A - Treasure
48B - Land Lot
835A - Key races
1622C - Set or Decrease
1682A - Palindromic Indices
903C - Boxes Packing
887A - Div 64
755B - PolandBall and Game
808B - Average Sleep Time
1515E - Phoenix and Computers
1552B - Running for Gold
994A - Fingerprints
1221C - Perfect Team
1709C - Recover an RBS
378A - Playing with Dice
248B - Chilly Willy
1709B - Also Try Minecraft
1418A - Buying Torches
131C - The World is a Theatre
1696A - NIT orz
1178D - Prime Graph
1711D - Rain
534A - Exam
1472A - Cards for Friends
315A - Sereja and Bottles
1697C - awoo's Favorite Problem
165A - Supercentral Point
1493A - Anti-knapsack
1493B - Planet Lapituletti